对对碰扑克牌、扑克对对碰游戏案例

下面是一个基于Python和Pygame的扑克对对碰游戏实现方案：

游戏设计思路

核心玩法

玩家需要在一副打乱的牌中找出相同的两张牌

点击两张相同点数的牌即可消除这对牌

在规定时间内消除所有牌即可获胜

技术要点

使用Pygame处理图形界面和用户交互

随机生成和布局扑克牌

实现卡牌的翻转动画效果

计时系统和得分系统

代码实现

python

import pygame

import random

import time

import sys

# 初始化pygame

pygame.init

# 屏幕设置

WIDTH, HEIGHT = 800, 600

screen = pygame.display.set_mode((WIDTH, HEIGHT))

pygame.display.set_caption("扑克对对碰")

# 颜色定义

WHITE = (255, 255, 255)

BLACK = (0, 0, 0)

GREEN = (100, 200, 50)

RED = (200, 60, 80)

BLUE = (70, 130, 230)

YELLOW = (240, 220, 90)

# 卡片设置

CARD_WIDTH, CARD_HEIGHT = 65, 85

MARGIN = 15

ROWS, COLS = 4, 10

TOTAL_CARDS = ROWS * COLS

# 确保牌数是偶数

assert TOTAL_CARDS % 2 == 0, "卡牌总数必须是偶数

class Card:

def __init__(self, value, x, y):

self.value = value # 牌的值，从1到13，代表A到K

self.x = x

self.y = y

self.width = CARD_WIDTH

self.height = CARD_HEIGHT

self.revealed = False # 是否翻开

self.matched = False # 是否已匹配

self.flipping = False # 是否正在翻转

self.flip_progress = 0 # 翻转进度

def draw(self):

# 绘制卡牌背景

if self.matched:

color = GREEN

we-poker加入俱乐部

else:

color = BLUE

# 绘制卡片主体

pygame.draw.rect(screen, color, (self.x, self.y, self.width, self.height), border_radius=8)

# 如果有翻转动画

if self.flipping:

progress = min(self.flip_progress / 30, 1.0)

# 计算中间矩形的宽度

middle_width = int(self.width * (1

abs(progress

0.5) * 1.8))

if middle_width > 0:

pygame.draw.rect(screen, BLACK,

(self.x + (self.width

middle_width) // 2, self.y,

middle_width, self.height),

border_radius=4)

# 如果牌面朝上，绘制牌值

elif self.revealed and not self.matched:

# 绘制白色内部区域

inner_margin = 5

pygame.draw.rect(screen, WHITE,

(self.x + inner_margin, self.y + inner_margin,

self.width

2 * inner_margin, self.height

2 * inner_margin),

border_radius=5)

# 根据牌值确定颜色和文本

color = RED if self.value

font = pygame.font.SysFont(None, 36)

text = font.render(str(self.value % 14 if self.value % 14 != 0 else 13), True, color)

text_rect = text.get_rect(center=(self.x + self.width // 2, self.y self.y + self.height // 2))

screen.blit(text, text_rect)

def update(self):

if self.flipping:

self.flip_progress += 1

if self.flip_progress >= 30:

self.flipping = False

self.revealed = not self.revealed

self.flip_progress = 0

def is_hovered(self, pos):

return self.x

def flip(self):

self.flipping = True

class Game:

def __init__(self):

self.cards = []

self.selected_cards = []

self.can_select_select = True

self.start_time = time.time

self.game_time = 120 # 2分钟游戏时间

self.score = 0

self.init_cards

def init_cards(self):

# 生成成对的牌值

card_values = [i for i in range(1, TOTAL_CARDS//2 + 1)]

card_values *= 2

random.shuffle(card_values)

# 创建卡片对象

self.cards.clear

for i in range(TOTAL_CARDS):

row = i // COLS

col = i % COLS

x = MARGIN + col * (CARD_WIDTH + MARGIN)

y = MARGIN + row * (CARD_HEIGHT + MARGIN) + 40 # 留出顶部空间显示信息

self.cards.append(Card(card_values[i], x, y))

def draw(self):

screen.fill(YELLOW)

# 绘制标题和信息栏

title_font = pygame.font.SysFont(None, 48)

info_font = pygame.font.SysFont(None, 32)

title_text = title_font.render("扑克对对碰", True, BLUE)

screen.blit(title_text, (WIDTH // 2

title

title_text.get_width // 2, 10))

# 绘制时间和分数

elapsed_time = max(0, self.game_time

(time.time

self.start_time))

minutes = int(elapsed_time // 60)

seconds = int(elapsed_time % 60)

time_text = info_font.render(f"时间: {minutes}:{seconds:02d}", True, BLACK)

score_text = info_font.render(f"分数: {self.score}", True, BLACK)

screen.blit(time_text, (20, 45))

screen.blit(score_text, (WIDTH

150, 45))

# 绘制所有卡片

for card in self.cards:

card.draw

# 如果游戏结束，显示结果

if self.is_game_over:

result_font = pygame.font.SysFont(None, 72)

if self.score >= TOTAL_CARDS // 2:

result_text = result_font.render("恭喜你赢了!", True, GREEN)

else:

result_text = result_font.render("游戏结束", True, RED)

screen.blit(result_text, (WIDTH // 2

result_text.get_width // 2, HEIGHT // 2

50))

restart_font = pygame.font.SysFont(None, 32)

restart_text = restart_font.render("点击任意位置重新开始", True, BLUE)

screen.blit(restart_text, (WIDTH // 2

restart_text.get_width // 2, HEIGHT // 2 + 30))

def update(self):

for card in self.cards:

card.update

# 检查选中的两张牌是否匹配

if len(self.selected_cards) == 2 and not any(card.flipping for card in self.selected_cards):

if self.selected_cards[0].value == self.selected_cards[1].value:

value:

# 匹配成功

for card in self.selected_cards:

card.matched = True

self.score += 1

else:

# 不匹配，翻回去

for card in self.selected_cards:

card.flip

self.selected_cards.clear

self.can_select = True

def handle_click(self, pos):

# 如果游戏结束，重新开始

if self.is_game_over:

self.__init__

return

# 如果不能选择新卡，返回

返回

if not self.can_select:

return

for card in self.cards:

if card.is_hovered(pos) and not card.revealed and not card.matched and not card.flipping:

card.flip

self.selected_cards.append(card)

if len(self.selected_cards) == 2:

self.can_select = False

break

def is_game_over(self):

# 检查是否所有牌都已匹配或时间用完

elapsed_time = time.time

self.start_time

return all(card.matched for card in self.cards) or elapsed_time > self.game_time

def main:

clock = pygame.time.Clock

game = Game

running = True

while running:

for event in pygame.event.get:

if event.type == pygame.QUIT:

running = False

elif event.type == pygame.MOUSEBUTTONDOWN:

game.handle_click(event.pos)

game.update

game.draw

pygame.display.flip

clock.tick(60)

pygame.quit

sys.exit

if __name__ == "__main__":

main

游戏功能说明

1. 游戏界面：

顶部 顶部显示游戏标题、剩余时间和当前分数

中央区域显示4×10的扑克牌阵列

2. 核心玩法：

点击两张相同的牌可以消除它们

成功消除一对牌得1分

游戏限时2分钟

3. 胜利条件：

在时间内消除所有牌获胜

超时则游戏失败

4. 视觉效果：

卡牌有翻转动画效果

已匹配的牌变为绿色

游戏结束后显示结果和重新开始选项

扩展建议

1. 增加难度级别：

简单 简单模式：较少牌对，更多时间

困难模式：更多牌对，更少时间

2. 添加音效：

卡牌翻转声音

匹配成功/失败音效

背景音乐

3. 增强视觉效果：

使用真正的扑克牌图像

添加匹配成功的特效动画

改进UI设计

这个游戏案例展示了基本的游戏开发概念，包括状态管理、用户交互处理和简单的动画效果，可以作为学习游戏开发的入门项目。